Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
time after launch, x in seconds, by the given equation. Using this equation, find out
the time at which the rocket will reach its max, to the nearest 100th of a second.
y = -16x2 + 168x + 92

Answer 1

9514 1404 393

Answer:

  5.25 seconds

Step-by-step explanation:

The vertex of the parabola defined by ax²+bx+c is located at x = -b/(2a).

The time to maximum altitude is ...

  x = -(168)/(2(-16)) = 168/32 = 5.25

The time at which maximum height is reached is 5.25 seconds after launch.