Question

What is the percent yield for carbon dioxide if 10.0 grams of carbon monoxide yielded
12.81 grams of carbon dioxide from the reaction below?
2 CO + O2 → 2 CO2

Answer 1

Answer:

$Y=81.5\%$

Explanation:

Hello!

In this case, for the given chemical reaction, since it is started with 10.0 g of CO, we can compute the theoretically yielded grams of carbon dioxide given the 2:2 mole ratio between them, on the chemical reaction:

$m_{CO_2}^{theoretical}=10.0gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO} *\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}^{theoretical}=15.7gCO_2$

Next, since the percent yield measures how much of the product is actually yielded, we compute it as shown below:

$Y=\frac{actual\ yield}{theoretical\ yield}*100\%$

Whereas the theoretical yield is 12.81 g and the theoretical one that 15.7 g. Therefore, the percent yield turns out:

$Y=\frac{12.81g}{15.7g}*100\%\\\\Y=81.5\%$

Regards!