Answer:
[tex]y=\frac{1}{3}x+\frac{5}{3}[/tex]
Step-by-step explanation:
- Slope of [tex]y=-3x-4[/tex] is the m of the general equation [tex]y=mx+b[/tex] which [tex]-3[/tex]
- The slope a line perpendicular to this line is the number that if multiplied with -3 will give us -1 so that [tex]\frac{1}{3}[/tex]
- With that slope and the point [tex](1,2)[/tex] use the formula
- [tex]y-y_1=m(x-x_1)\\y-(2)=\frac{1}{3} (x-(1))\\y-2=\frac{1}{3}x-\frac{1}{3}\\y=\frac{1}{3}x+\frac{5}{3}[/tex]