Respuesta :
Answer:
120 different ways
Step-by-step explanation:
Using the combination formula as shown;
nCr = n!/(n-r)!r!
If a stack of 10 different cards are shuffled and spread out face down. If 3 cards are turned face up, the number of different ways 3cards combinations are possible is expressed as;
10C3 = 10!/(10-3)!3!
10C3 = 10!/(7)!3!
10C3 = 10*9*8*7!/7!*3*2
10C3 = 10*9*8/3*2
10C3 = 720/6
10C3 = 120 different ways
Hence there are 120 different card combinations
The different 3-card combinations that are possible are; 120 possible combinations
This is a combination probability problem with the formula;
nCr = n!/((n-r)!r!)
Where;
n is sample size
r is possible choice
In this case;
n = 10
r = 3
Thus;
The different 3-card combinations possible are;
10C3 = 10!/((10 - 3)!3!)
>> 10!/(7! × 3!)
>> 120
Thus,there are 120 possible combinations of 3 different cards.
Read more at; https://brainly.com/question/23885729