Question

Determine the intercepts of the line. 7x-5=4y-67x−5=4y−67, x, minus, 5, equals, 4, y, minus, 6 xxx-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis yyy-intercept: \Big((left parenthesis ,,comma \Big))

Answer 1

Given:

The equation of line is

$7x-5=4y-6$

To find:

The x and y-intercept of the given line.

Solution:

We have,

$7x-5=4y-6$

Putting x=0, we get

$7(0)-5=4y-6$

Add 6 on both sides.

$0-5+6=4y$

$1=4y$

Divide both sides by 4.

$\dfrac{1}{4}=y$

So, the y-intercept is $\left(0,\dfrac{1}{4}\right)$.

Putting y=0 in given equation, we get

$7x-5=4(0)-6$

Add 5 on both sides.

$7x=-6+5$

$7x=-1$

Divide both sides by 7.

$x=\dfrac{-1}{7}$

So, the x-intercept is $\left(-\dfrac{1}{7},0\right)$.

Answer 2

Answer:

x intercept: (-1/7 , 0)

y intercept: (0, 1/4)

Step-by-step explanation: