Answer:
130 moles of water might be produced by the reaction.
Explanation:
We state the equation for production of water:
2H₂(g) + O₂ (g) → 2H₂O (l)
Moles of hydrogen: 130
Moles of oxygen: 60
We state that the limting reactant is the oxygen
For 2 moles of hydrogen, we need 1 mol of oxygen
For 130 moles of hydrogen, we would need 65 moles, and we only have 60. Ratio is 2:1
1 mol of O₂ can produce 2 moles of water
Then, 60 moles of O₂ will produce (60 . 2) /1 = 130 moles