Answer:
Explanation:
When we go back and look at Kepler's third law. Kepler's third law states that "the square of the period is proportional to the cube of the semi-major axis of the orbit". P²µa³
where a is the semi-major axis of orbit,
P is the period of orbit
The orbit in question is the distance from the center of Earth. If the satellite spirals in as a result of air friction, then it decreases and, so does P.
Note that P = 2πa / V or Vµ1 / a0.5 .
From the formula, we can see that a decrease in the value of a, will lead to an Increase in the value of V.
