Question

An object is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground. Calculate: a) The time it takes the object to reach the ground b) Its velocity when it reaches the ground.

Answer 1

Answer:

0.41s

8.01m/s

Explanation:

Using the formula; v = u + at

Where;

u = initial velocity (m/s)

v = final velocity (m/s)

t = time (s)

a = acceleration (m/s²)

According to the provided information, u = 4m/s, s = 8m,

V = u + at

4 = 0 + 9.8t

4 = 9.8t

t = 0.41s

b) v = u + at

v = 4 + 9.8(0.41)

v = 4 + 4.018

v = 8.018m/s