Question

Suppose datagrams are limited to 1,500 bytes (including header) between source Host Aand destination Host B. Assuming a 20-byte IPheader, how many datagrams would be required to send an MP3 consisting of 5 million bytes? Explain how you computed your answer.

Answer 1

Answer:

3424 datagrams would be required

Explanation:

Mp3 file size = 5 million bytes

assuming the data is carried in TCP segments with each TCP segment have 20 bytes of header

Therefore each datagram can carry at least : ( 1500 - 40 ) = 1460 bytes

Therefore the number of datagrams required = $[\frac{5*10^6}{1460} ]$    =  3424

Answer 2

The MP3 file to be transmitted does have a size of 5 million bytes or $5 \times 10^6\ \ bytes$. Suppose that information is moved via TCP segments with a TCP header size of 20 bytes.

• Each IP header is 20 bytes long, and the TCP header is also 20 bytes long. Therefore, we use 40 bytes out of a total of 1500 bytes for IP and TCP headers.
• Then, in each datagram, we can send $1500-40 = 1460$ bytes of MP3 files. So, overall number of data packets necessary:

         $= \frac{\text{Total MP3 Size}}{\text{ MP3 Size}}$

• calculating the each datagram that is capable of transporting:

                 $\to \frac{5000000}{ 1460} \\\\ \to 3424.65753425 \\\\\to 3425 \ \ Datagrams.$

• Except for the last one, all datagrams would be 1500 bytes in size. Your final datagram will be 1000 bytes long, i.e,

   $\to 1460 \times 0.65753425 \\\\ \to 960 + 40 \ \text{(Bytes of Header)} \\\\ \to 1000 \ Bytes$

Learn more:

brainly.com/question/16666220