Question

A child is sitting on the outer edge of a merry-go-round that is 18 m in diameter. If the merry-go-round makes 4.9 rev/min, what is the velocity of the child in m/s?
a.
9.2 m/s
b.
4.6 m/s
c.
0.74 m/s
d.
1.75 m/s

Answer 1

Answer:

b.  4.6 m/s

Explanation:

the formula for calculating the linear velocity is expressed as;

v = wr

w is the angular velocity

r is the radius

r = d/2 = 18/2

r = 9 m

Given that 1rev/min = 0.10472rad/s

4.9 rev/min = x

x = 4.9 * 0.10472

x = 0.513128 rad/s

Substitute into the given formula;

v = 9 * 0.513128

V = 4.61m/s

Hence the velocity of the child in m/s is 4.6m/s