Question

It the same child has a velocity of 2 m/s half-way down the slide, what is his kinetic energy?

Answer 1

Answer:

$\frac{1}{2} \times m \times {v}^{2} \\ \frac{1}{2} \times m \times {2}^{2} \\ 2 \times m$

I dont the child mass...you should substitute that value to (m)

then you can get your answer