Answer:
The value of [tex]r=33[/tex] which makes the equation true.
Step-by-step explanation:
Given the equation
[tex]\frac{r}{-11}=-3[/tex]
We have to find the value of r for which the equation must be true.
solving the equation
[tex]\frac{r}{-11}=-3[/tex]
Multiply both sides by -11
[tex]\frac{r\left(-11\right)}{-11}=\left(-3\right)\left(-11\right)[/tex]
[tex]r=33[/tex]
Therefore, the value of [tex]r=33[/tex] which makes the equation true.
VERIFICATION:
Putting [tex]r=33[/tex] in the equation
[tex]\frac{r}{-11}=-3[/tex]
[tex]\frac{33}{-11}=-3[/tex]
[tex]-3=-3[/tex] ∵ [tex]\frac{33}{-11}=-3[/tex]
L.H.S = R.H.S
Therefore, the value of [tex]r=33[/tex] which makes the equation true.