Question

The air in a tire pump has a volume of 1.50L at a temperature of 5◦C. If the temperature is increased to 30◦C and the pressure remains constant, what is the new volume? Hurry Please!

Answer 1

Answer:

1.6L

Explanation:

Given parameters:

Initial volume  = 1.5L

Initial temperature  = 5°C  = 5 + 273  = 278K

Final temperature  = 30°C = 30 + 273  = 303K

Unknown:

Final or new volume  = ?

Solution;

Since pressure is constant, we simply apply Charles's law to solve this problem.

Using the expression below,

          $\frac{V_{1} }{T_{1} }$   = $\frac{V_{2} }{T_{2} }$

V and T are volume and temperature

1 and 2 are initial and final states

  Insert the parameters and solve;

         $\frac{1.5}{278}$   = $\frac{V_{2} }{303}$

          278V₂  = 1.5 x 303

                V₂  = 1.6L