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18-11-2020
Chemistry

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Balance the following equation:
B203(s) + HF(l) => BF3(g) + H20(l)

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vincentpeyton004 vincentpeyton004

18-11-2020

20 B203(s) + 12180 HF(l) = 4060 BF3(g) + 609 H20(l)

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