Question

A small car uses about 130000J of energy in the form of gasoline. The car converts that energy to a kinetic energy of 53000J. What is the efficiency of this conversion?

Answer 1

Explanation:

Given parameters:

Energy input  = 130000J

Energy output = 53000J

Unknown:

Efficiency of the conversion = ?

Solution:

Efficiency is the percentage of work output to work input;

  Mathematically;

 Efficiency  = Energy output/ Energy input x 100

 Efficiency  = 53000/130000 x 100 = 40.8%