Answer:
∠1 ≅ ∠2 ⇒ proved down
Step-by-step explanation:
#11
In the given figure
∵ BA // CF
∵ BC is a transversal
∵ ∠1 and ∠BCF are interior alternate angles
∵ The interior alternate angles are equal in measures
∴ m∠1 = m∠BCF
∴ ∠1 ≅ ∠BCF ⇒ (1)
∵ BC // ED
∵ CF is a transversal
∵ ∠BCF and ∠2 are corresponding angles
∵ The corresponding angles are equal in measures
∴ m∠BCF = m∠2
∴ ∠BCF ≅ ∠2 ⇒ (2)
→ From (1) and (2)
∵ ∠1 and ∠2 are congruent to ∠BCF
∴ ∠1 and ∠2 are congruent
∴ ∠1 ≅ ∠2 ⇒ proved
