Question

What is the slope of the line that goes through points (−3,−4) and (−7,16)? please help

Answer 1

Answer:

5

Step-by-step explanation:

slope = $\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

The second y point is 16 and the first is -4, so:

(16) - (-4)

Which can be written as 16 + 4 because a double negative makes a positive. Do the same for the x points, -7 and -3:

(-7) - (-3)

(-7) + (3)

Now solve both of them:

16 + 4 = 20

(-7) + 3 = -4

Remember, the slope formula is y over x, so we still need to put it into the fraction form:

$\frac{20}{-4}$

You can reduce this to $-\frac{5}{1}$, or 5.

Answer 2

The slope of the line will be "-5".

Given points are:

• $(x_1,y_1) = (-3,-4)$
• $(x_2,y_2) = (-7,16)$

As we know the formula,

→ Slope, $m = \frac{y_2-y_1}{x_2-x_1}$

By substituting the values, we get

                  $= \frac{16-(-4)}{-7-(-3)}$

                  $= \frac{16+4}{-7+3}$

                  $= -\frac{20}{4}$  

                  $= -5$

Thus the above answer is correct.

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