Answer:
1.4 g
Explanation:
Step 1: Write the balanced combustion reaction
CaC₂O₄ + 1/2 O₂ ⇒ CaO + 2 CO₂
Step 2: Calculate the moles corresponding to 3.2 g of CaC₂O₄
The molar mass of CaC₂O₄ is 128.10 g/mol.
3.2 g × 1 mol/128.10 g = 0.025 mol
Step 3: Calculate the moles of CaO formed from 0.025 moles of CaC₂O₄
The molar ratio of CaC₂O₄ to CaO is 1:1. The moles of CaO formed are 1/1 × 0.025 mol = 0.025 mol.
Step 4: Calculate the mass corresponding to 0.025 moles of CaO
The molar mass of CaO is 56.07 g/mol.
0.025 mol × 56.07 g/mol = 1.4 g
