Answer:
x = 14
y = 4
Explanation:
Ok so, just from looking at the two triangles i can tell they're congruent right triangles. I used different colors to show which sides of the triangle correspond and are equal to each other in my attatched photo.
So the side thats equal to x is the same length as the side that's equal to y+10 on the other triangle.
So we can write the equation x = y + 10.
Using this same method, the side that's equal to x + 2 is the same length as the side that's equal to 4y on the other triangle.
So, we can write the equation 4y = x + 2.
Now we have the equations [tex]\left \{ {{x=y+10} \atop {4y=x+2}} \right.[/tex] you could rewrite to be in slope- intercept form so they're easier to graph. But a graphing calculator online would plot it just fine.
If you graph these two equations they'll intersect at the solution ( 14, 4 ). I'll include the graph in my images as well.
To check your answer, you can plug in x and y and see if the triangle sides end up being the same length. I did and it was correct.
