Question

The sum of two numbers is 72, and their difference is 40. Find the numbers.

Answer 1

Answer:

56 and 16

Step-by-step explanation:

Set up equations!

x+y=72

x-y=40

You can solve for this by crossing out y as it becomes eliminated. You are left with 2x= 112. Then solve, so x= 56. Take 56 for x and plug it into one of the equations and solve for y. 56-y=40-----> y= 16. The numbers are 16 and 56.

Answer 2

Using a system of equations, it is found that the numbers are 16 and 56.

• The numbers are unknown, so we are going to call them x and y.

Their sum is of 72, thus:

$x + y = 72 \rightarrow y = 72 - x$

Their difference is of 40, thus:

$x - y = 40$

Since $y = 72 - x$

$x - (72 - x) = 40$

$2x = 112$

$x = \frac{112}{2}$

$x = 56$

Then:

$y = 72 - x = 72 - 56 = 16$

The numbers are 16 and 56.

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