9514 1404 393
Answer:
32.8 m/s
Step-by-step explanation:
The function is actually ...
[tex]v(d) = \sqrt{2gd}[/tex]
Filling in the given values, the velocity is about ...
[tex]v(55) = \sqrt{2\cdot9.8\cdot55}=\sqrt{1078}\approx32.8\text{ m/s}[/tex]
The velocity at the end of the free-fall is about 32.8 meters per second.