Question

The Heat of vaporization for NH3= 1360 J/g. Calculate the quantity of heat energy (in kJ)
needed to completely boil a 155 gram sample at its boiling point
general formula

Answer 1

Answer:

$Q=210.8kJ$

Explanation:

Hello!

In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:

$Q=m\Delta H_{vap}$

In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:

$Q=155g*1360J/g\\\\Q=210.8kJ$

Best regards!