Question

What is the equation of the line perpendicular to y=1/4-5 trough the point (4,-3)

Answer 1

Answer:

The equation is y=-4x+13

Solutions:

y=1/4-5 (4,-3)

y=mx+b

The new slope = -4/1x+b

-3=-4/1(4)+b

-3=-16+b

+16 +16

13=b

y=-4x+13