Question

The table shows the temperature (y) at different altitudes (x).
This is a linear relationship. (Example 2)
2)Find the slope of this relationship

3)Find the y-intercept for this relationship

4)Write an equation in slop intercept form that represents this relationship

5)Use the equation to determine the temperature at an altitude of 5000 feet

Answer 1

Answer/Step-by-step explanation:

2. Using two pairs of values, (0, 59) and (2,000, 51),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{51 - 59}{2,000 - 0} = \frac{-8}{2,000} = -\frac{1}{250}$

3. The y-intercept is the value of y when x = 0. Thus, x = 0, when y = 59. Therefore,

y-intercept (b) = 59

4. To write an equation in slope-intercept form, simply substitute m = -¹/250, and b = 59, in $y = mx + b$

✅$y = -\frac{1}{250}x + 59$

5. Substitute x = 5,000 in $y = -\frac{1}{250}x + 59$.

$y = -\frac{1}{250}(5,000) + 59$

$y = -20 + 59$

$y = 39$

At an altitude of 5,000 ft, temperature would be 39°F