Question

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2. How many atoms of zinc are present in 0.48 mol of zinc?
(show solution)​

Answer 1

Answer:

2.89 × 10²³ atoms of zinc

Explanation:

The number of atoms of zinc can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.48 × 6.02 × 10²³

We have the final answer as

2.89 × 10²³ atoms of zinc

Hope this helps you

Answer 2

Answer:

2.89× 10²³ atom

Explanation:

Given data:

Number of atoms of Zn = ?

Number of moles of Zn = 0.48 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ atom

0.48 mol ×  6.022 × 10²³ atom / 1mol

2.89× 10²³ atom