Question

Write an equation of the line passing through point P that is perpendicular to the given line.
P(6, 10), y = -3x + 13

Answer 1

Answer:

y = 1/3x + 8

Step-by-step explanation:

*perpendicular means the reciprocal slope of the given line

m = 1/3

y = 1/3x + b

*plug in points with the point-slope equation

10 = 1/3(6) + b

10 = 2 + b

b = 8

*now plug everything into the equation

y = 1/3x + 8

Answer 2

Answer:

y = 1/3x + 8

Step-by-step explanation:

1. Find slope of y = -3x+13

(m = -3)

2. Compute slope for perpendicular line

(m = 1/3)

basically, to find the perpendicular slope, you swap the numerator and denominator of your slope and swap it from negative to positive. (If you started with a positive slope it would turn negative)

3. Find the line with slope m=1/3 that passes through (6,0)

(y = 1/3x + 8)