Question

Richard throws a stone over a bridge into the river below. The stone's
height, in meters above the water, x seconds after it is thrown is modeled
by h () = = -5 (x – 8) (x + 4).
a.) How many seconds after being thrown will the stone meet its maximum
height?
b.) What is the maximum height of the stone?

Answer 1

Answer:

a.) In 1 second stone reach its maximum height

b.) 45 m

Step-by-step explanation:

v=  

2

u

​  

=u−gt

=u−  

2

3

​  

g

t=1.5s

u=30m/s

h=  

2g

u  

2

 

​  

 

h=  

2×10

30×30

​  

=45m