Question

An 800 N man stands on a scale in a motionless elevator. When the elevator begins to move, the scale
reads 650 N. Find the magnitude and direction of the elevator’s acceleration.

Answer 1

Answer:

Net force = 800 – 650

= 150 N

150 = (800 ÷ 9.8) a  

a = 1470 ÷ 800

= 1.8375 m/s^2, downwards

Answer 2

The downward acceleration of the man in the elevator is 1.84 m/s².

The given parameters;

• weight of the man, W = 800 N
• reading of the scale, R = 650 N

The magnitude of the and direction of the elevator’s acceleration is calculated as follows;

R = W + F

When the reading on the scale is less than the actual weight, the elevator is moving downwards.

R = W - F

650 = 800 - ma

ma = 800 - 650

ma = 150

where;

m is mass of the man

The mass of the man is calculated as follows;

W = mg

800 = 9.8m

$m = \frac{800}{9.8} = 81.63 \ kg$

The acceleration of the man is calculated as follows;

81.63a = 150

$a = \frac{150}{81.63} = 1.84 \ m/s^2$

Thus, the downward acceleration of the man in the elevator is 1.84 m/s².

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