Answer:
Width = [tex]7\frac{11}{16}[/tex] inches
Step-by-step explanation:
Given
[tex]End_1 = 2\frac{3}{4}[/tex]
[tex]End_2 = 10\frac{7}{16}[/tex]
Required
Determine the width of frame in between
To do this, we simply calculate the difference between both ends:
i.e.
[tex]Difference = End_2 - End_1[/tex]
This gives:
[tex]Difference = 10\frac{7}{16} - 2\frac{3}{4}[/tex]
Convert to improper number
[tex]Difference = \frac{167}{16} - \frac{11}{4}[/tex]
Take LCM
[tex]Difference = \frac{167 - 44}{16}[/tex]
[tex]Difference = \frac{123}{16}[/tex]
[tex]Difference = 7\frac{11}{16}[/tex]
Hence, the width of the frame is [tex]7\frac{11}{16}[/tex] inches