Question

Question 2 (2 points)
Saved
How many grams of water do will you need to prepare 480 g of 8.5% solution of
C6H12O6

Answer 1

Answer:

$m_w=439.2g$

Explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

$\%m/m=\frac{m_{solute}}{m_{solution}} *100\%$

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

$m_{solute}=\frac{\%m/m*m_{solution}}{100\%}$

Thus, by plugging in the data, we obtain:

$m_{solute}=\frac{8.5\%*480g}{100\%}=40.8g$

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

$m_w=m_{sol}-m_{solute}=480g-40.8g\\\\m_w=439.2g$

Best regards!