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Answer:
Since the object is floating, the buoyant force equals the weight of the water displaced:
W = d g v where d is the density of water and v = V/2 where v is the volume of the water displaced and v = V/2 where V is the volume of the object.
W = 1000 kg/m^3 * 9.8 m/s^2 * (3.5 /2 m^3)
W = 17150 kg m / s^2 = 17150 N
When an object floats with half its volume beneath the surface of the water. If the volume of the object is 3.5 m,then the weight of the object would be 17167.5 N if the density of water is 1000 kg/m3
What is density?
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
The density is the reciprocal of the specific volume of any substance.
The mathematical formula for density is given below
ρ =m /V
where ρ is the density of the substance
m is the mass of the substance
V is the volume of the substance
As given in the problem an object floats with half its volume beneath the surface of the water. The volume of the object is 3.5 m
The density of water is 1000 kg/m3
According to the Archimedes principle, the buoyancy force acting on the floating object is equal to the weight of the fluid displaced by it
W = ρ g V
Given the object floats with half its volume beneath the surface of the water means the volume of the water displaced is half of the volume of the object
V=3.5/2 m³
W = 1000×9.81×3.5/2
= 17167.5 N
Thus, the weight of the object is 17167.5 N
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