Question

In an inter-barangay basketball league, the team from Hermana Fausta has won 12 out of 25 games, a winning percentage of 48%. We have seen that they need to win 8 games consecutively to raise their percentage to 60%. What will their winning percentage be if they win 10, 20, 30, 50, 100 games? Can they reach a 100% winning percentage? (hint: try to substitute 300 games). Write your interpretation on the space provided.​

Answer 1

Answer:

To get the percecentage of winning can be find out with the help of :

P (x) = numerator+x/denominator+x

so the formula for the case would be:

P(x) = 12+x/25+x

- x = 10 matches

p(x) = (12 + 10)/(25 + 10)

= 22/35

= .6285  or appr 0.63%

-  x = 20 matches

p(x) = (12 + 20)/(25 + 20)

= 32/45

= 0.71  or 0.7 appr %

- x = 30 matches

p(x) = (12 + 30)/(25 + 30)

= 42/55

= 0.76  or 0.8 appr %

- x = 50 matches

p(x) = (12 + 50)/(25 + 50)

= 62/75

= .0.8  or 0.9appr %

:- x = 100 matches

p(x) = (12 + 100)/(25 + 100)

= 112/125

= .0.8  or 0.9 appr %

even for the 300 wins, the percentage of winning will be 0.96.

It is now clear that no mater what games they win they can not reach to 100% winning percentage as denominator is higher than the numerator and it is logical if someone already lost 13 games how can be they get 100%