Question

In an equation of the form k = ax^2 + bx + c with a > 0, the least possible value of k occurs at x = -b/(2a). In the equation k = (6x + 12)(x - 8), what is the least possible value for k?

Answer 1

Answer:

$k= 6x^{2} -36x-96$

Is what I got in a calculator but however, if you'd try and solve for K you won't get a complete answer.

Hope this helped :)