Respuesta :

I think it’s 2x^1/3y hope this helped

Answer:

[tex]\frac{2x}{3y}[/tex]

please give me brainliest!

Step-by-step explanation:

[tex]\frac{\sqrt{4x^2}}{3y} = \frac{2x}{3y}[/tex]

I'm assuming that the entire 4x^2 term is under the radical sign. If it isn't, then

[tex]\frac{\sqrt{4}x^2}{3y} = \frac{2x^2}{3y}[/tex]

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