Question

Solve for c.

a−b+c‾‾‾‾‾‾‾‾‾√=3




A. c=3−a+b

B. c=9−a‾√+b‾√

C. c=3−a‾√+b‾√

D. c=9−a+b

Answer 1

The solution for c in the given equation is $c = 9 - a +b$. The correct option is the fourth option $c = 9 - a +b$

From the question,

We are to solve for c in

$\sqrt{a-b+c} =3$

To do this,

First, we will take the squares of both sides

That is,

$(\sqrt{a-b+c} )^{2} = 3^{2}$

Then, we get

$a-b+c = 9$

Now, we will add (b - a) to both sides of the equation

That is,

$a - b + c + b -a = 9 + b -a$

Then, we can write that

$a -a - b +b + c = 9 -a + b$

∴ $c = 9 - a +b$

Hence, the solution for c in the given equation is $c = 9 - a +b$. The correct option is the fourth option $c = 9 - a +b$

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