Question

write an equation of the line that passes through point (-8,-5) and has the slope m=-1/4

Answer 1

Answer:

x+4y=-28

Step-by-step explanation:

The equation of line in point-slope form is given by :

$(y-y_1)=m(x-x_1)$

We have,

$(x_1,y_1)=(-8,-5)\\\\m=\dfrac{-1}{4}$

So,

$(y-(-5))=\dfrac{-1}{4}\times (x-(-8))\\\\y+5=\dfrac{-1}{4}(x+8)\\\\4y+20=-x-8\\\\x+4y=-20-8\\\\x+4y=-28$

Hence, the required equation is x+4y=-28.