Answer:
[tex] \rm (x^2 - 3x - 33)\div(x + 4) = x - 7 - \dfrac{5}{x + 4} [/tex]
Step-by-step explanation:
[tex] \rm\qquad\quad\quad{x-7}\\ \begin{array}{cc} \cline{2 - 2}\rm x + 4 )&\rm \ x^2 - 3x -33\\&\rm x^2 + 4x \\ \cline{2-2}& \rm \ \ \ \ -7x-33\\ &\sf \ - 7x-28 \\ \cline{2-2} & \rm \ \ -5 \\ \cline{2-2} \end{array} [/tex]
Quotient → x - 7
Remainder → -5
Divisor → x + 4
