Question

Another coin is thrown up into the air and hit the ground after 6s with a velocity of -60 m/s after experiencing an acceleration of -9.8 m/s2. What was its initial velocity?

Answer 1

Answer:

Vf = Vi + a t       fundamental equation

-60 m/s= Vi - 9.8 m/s^2 * 6 sec      taking upward direction as positive

Vi =58.8 m/s - 60  m/s = -1.2 m/s   so the coin was initially thrown downward

As a check take the downward direction as positive

Vf = 1.2 m/s + 58.8 m/s = 60 m/s