Answer:
The two numbers are 40 and 3
Step-by-step explanation:
Assume that the first number is x and the second number is y
∵ Four tenths = [tex]\frac{4}{10}[/tex] = 0.4
∵ One tenth = [tex]\frac{1}{10}[/tex] = 0.1
∵ Four tenths of 1st number increased by the 2nd number equals 19
∵ The 1st number = x and the 2nd number = y
∴ 0.4x + y = 19 ⇒ (1)
∵ One tenth of the 1st number decreased by the 2nd number is equal to 1
∴ 0.1x - y = 1 ⇒ (2)
Now we have a system of equations to solve it
→ Add equations (1) and (2) to eliminate y
∵ (0.4x + 0.1x) + (y + -y) = (19 + 1)
∴ 0.5x + 0 = 20
∴ 0.5x = 20
→ Divide both sides by 0.5 to find x
∵ [tex]\frac{0.5x}{0.5}[/tex] = [tex]\frac{20}{0.5}[/tex]
∴ x = 40
→ Substitute the value of x in equation (1) or (2) to find y
∵ 0.4(40) + y = 19
∴ 16 + y = 19
→ Subtract 16 from both sides
∴ 16 - 16 + y = 19 - 16
∴ y = 3
∴ The two numbers are 40 and 3
