Question

Tim throws a stick straight up in the air from the ground. The function h = -16t^2+ 48t models the height, h, in feet, of
the stick above the ground after t seconds. Which inequality can be used to find the interval of time in which the stick
reaches a height of more than 8 feet?

Answer 1

Answer:

$-2t^2+ 6t -1 > 0$

Step-by-step explanation:

Function Modeling

The height h in feet of the stick threw by Tim is modeled by the function:

$h = -16t^2+ 48t$

where t is the time in seconds.

It's required to write an inequality that can be used to find the interval of time in which the stick reaches a height of more than 8 feet, i.e. h > 8.

Using the given model, we write the inequality:

$-16t^2+ 48t > 8$

Dividing by 8

$-2t^2+ 6t > 1$

Subtracting 1, we get the required inequality:

$\mathbf{-2t^2+ 6t -1 > 0}$

Answer 2

Answer:

you want more than 8 feet so the answer would be -16t^2+48t>8

Step-by-step explanation:

h=-16t^2+48t

-16t62+48t>8

-16t^2+48t=8

divide both sides of the equal sighn by 8

-2t^2+6t=1

put the symbol back in

-2t^2+6t>1

substitute a random mumber for t

-2(5)^2+6(5)>1

-10^2+30>1

subtract 30 from both sides

100>-29

state is true so -16t62+48t>8 is the correct answer