Answer:
The graph of the line that contains the point [tex](-3,1)[/tex] with a slope of 2/3.
Step-by-step explanation:
As the line contains the point (-3, 1) with a slop 2/3
Given the slop-intercept form of the line equation
y = mx+b
Here,
Substituting the values in the slop-intercept form of the line equation
[tex]y = mx+b[/tex]
[tex]1 = \frac{2}{3} (-3) + b[/tex]
[tex]1 =- 2 + b[/tex]
switching sides
[tex]-2+b=1[/tex]
[tex]b=3[/tex]
Now Substituting the value of [tex]b=3[/tex] in the slop-intercept form of the line equation
[tex]y = mx+b[/tex]
[tex]y=\frac{2}{3} x+3[/tex]
Hence, the line of the equation will be: [tex]y=\frac{2}{3} x+3[/tex]
Therefore, the graph of the line that contains the point [tex](-3,1)[/tex] with a slope of 2/3.