Respuesta :

Answer:

The graph of the line that contains the point [tex](-3,1)[/tex] with a slope of 2/3.

Step-by-step explanation:

As the line contains the point (-3, 1) with a slop 2/3

Given the slop-intercept form of the line equation

y = mx+b

Here,

  • m = slope
  • b = y-intercept

Substituting the values in the slop-intercept form of the line equation

[tex]y = mx+b[/tex]

[tex]1 = \frac{2}{3} (-3) + b[/tex]

[tex]1 =- 2 + b[/tex]

switching sides

[tex]-2+b=1[/tex]

[tex]b=3[/tex]

Now Substituting the value of [tex]b=3[/tex] in the slop-intercept form of the line equation

[tex]y = mx+b[/tex]

[tex]y=\frac{2}{3} x+3[/tex]

Hence, the line of the equation will be:  [tex]y=\frac{2}{3} x+3[/tex]

Therefore, the graph of the line that contains the point [tex](-3,1)[/tex] with a slope of 2/3.

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