Answer:
The cost of using 18 HCF = $40.39
Step-by-step explanation:
A linear function is one that has a constant rate of change for all the values within the distribution. For a linear function, there is a constant, and that constant is known as the slope or gradient of the linear function.
Let us first calculate this constant (slope).
Let:
X₁ = 14 HCF, Y₁ = $33.79, X₂ = 27 HCF, Y₂ = $55.24, m = slope
[tex]m = \frac{Y_2-Y_1}{X_2 - X_1} \\m = \frac{55.24 - 33.79}{27-14} \\m = \frac{21.45}{13} \\m = 1.65[/tex]
at any two points on the linear function, the rate of change of the cost to HCF = 1.65
Now, Let X₃ = 18 HCF, Y₃ = cost for using 18 HCF
[tex]m = \frac{Y_3 - Y_1}{X_3-X_1} \\where\ m= 1.65\\1.65 = \frac{Y_3-33.79}{18-14}\\1.65 = \frac{Y_3 - 33.79}{4} \\6.6 = Y_3 - 33.79\\Y_3 =6.6+33.79\\Y_3 = 40.39[/tex]
Therefore, the cost of using 18 HCF = $40.39
N:B X₂ and Y₂ can also be used with X₃ and Y₃ to find Y₃. You can try it out, you should get the same result