Solution :
Assume that the length of the string is constant and the string is inextensible.
The length of the string between the truck and pulley 1 is constant. Also total length of string connecting the truck wrapping pulley 1 and passing over pulley 2 is also constant.
Therefore, from the figure,
L+a+a = constant
L+2a = C
Differentiating both sides w.r.t time, we get
[tex]$\frac{dL}{dt}+2\frac{da}{dt}=\frac{dC}{dt}$[/tex]
[tex]$\frac{dL}{dt}=V_T = 18 \ ft/s$[/tex]
[tex]$18 + 2 \frac{da}{dt}=0$[/tex]
where, [tex]$\frac{da}{dt} = V_C = $[/tex] speed of the car
So
[tex]$18+2V_C=0$[/tex]
[tex]$V_C = -9 \ ft/s$[/tex] (only magnitude of speed has significance, so negative sign
is ignored )
Therefore, the speed of the car is 9 ft/s