Answer:
The answer is "k= 16 units and L=0 units"
Explanation:
Given:
[tex]Q = (0.5K^{\frac{1}{3}} + 0.5L^{\frac{1}{3}})^3[/tex]
Since K and L are ideal replacements, their company should select its cheapest of two for production. Its business chooses only money.
[tex]\to Q(K,L)=(0.5 K^{\frac{1}{3}})^3 \\\\\to 8= 0.5K^{(\frac{1}{3})}^3\\\\\to 2= 0.125 \ K \\\\\to K=16[/tex]
[tex]K=16 \ units \\\\ L=0 \ units[/tex]