Question

A wolf population is growing exponentially. In 2011, 129 wolves were counted. By 2013, the population had reached 236 wolves. Write the equation representing the population N of wolves over time t. Write your answer in the form a(b)^t. Round your b value to 3 decimal places. ​

Answer 1

Answer:

129 $(1.3526)^{t}$

Step-by-step explanation:

Assuming N = $ab^t$

t = number of years after 2011

N = number of wolves

When  t = 0 , N = 129

129 = $ab^0$

a = 129

N = 129$b^{t}$

When t = 2 , N = 236

therefore 236 = 129 $b^{2}$

$b^{2}$  = $\frac{236}{129}$

therefore; b = 1.3526

Answer expressed in the form of a(b)^t.

129 $(1.3526)^{t}$