Question

Write both the complete electron- configuration notation and the noble-gas notation for iodine, I. How many inner-shell electrons does an iodine atom contain?

Answer 1

Answer:

Iodine has an atomic number of 53

Electronic configuration - 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2  4d^10 5p^5

Noble gas configuration - [kr]4d^10 5s^2 5p^5

Iodine have 7 valence shell electron and 46 inner shell electron in the ground state.

Answer 2

The atomic number of Iodine is 53.

Additionally, the Electronic configuration of Iodine is as follows;

• 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵

The Noble gas notation for Iodine is;

• [Kr]4d^10 5s^2 5p^5

Ultimately, Iodine is a member of the halogen group of the periodic table and hence, has 7 valence shell electron and 46 inner shell electron in the ground state.

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