Question

At 4 seconds after starting, a cyclist is traveling 10 m/sec. At 6 seconds, he is traveling 20 m/sec. What is his average acceleration from 4 seconds to 6 seconds?

Answer 1

Answer:

The average acceleration of the cyclist is 5 m/s²

Explanation:

Given;

initial velocity of the cyclist, u = 10 m/s

final velocity of the cyclist, v = 20 m/s

initial time of the cyclist, t₁ = 4 seconds

final time of the cyclist, t₂ = 6 seconds

The average acceleration is given by;

$a = \frac{dv}{dt}\\\\a = \frac{v-u}{t_2-t_1}\\\\a = \frac{20-10}{6-4}\\\\a = 5 \ m/s^2$

Therefore, the average acceleration of the cyclist is 5 m/s²