Respuesta :
Answer:
CH3-CH2-CH2-CH2-CH2-OH. (1-PENTANOL)
Explanation:
The given compound is Pente-1-ne
Hydroboration oxidation reagent - BH3 +H2O2 + OH-
The reaction is initiated by boron hydride which attacks the terminal carbon because the middle carbon + charge will be stabilized by +I effect of the parent carbon chain. This similar process will happen thrice and all the hydrogens of Boron hydride will be lost and carbon chain of Pent-1-ene will be attached to boron and it will form TRIPENTYL BORANE, Then we will add H2O2+ OH- and finally OH- will be attached to the parent carbon chain and
1-PENTANOL will be formed.
CH3-CH2-CH2-CH=CH2 + HBO → CH3-CH2-CH2-CH2-CH2-OH
1-PENTANOL
