Question

A chemist conducts an experiment in which 2.0 L of hydrogen gas is collected over water at 1 atm and 298 K. Remember the pressure due to the hydrogen gas is 0.97 atm. Using the combined gas law, calculate the volume in L of the dry hydrogen gas at 273 K and a pressure of 1 atm.

Answer 1

Answer:

$V_2=1.80L$

Explanation:

Hello!

In this case, since in this problem we can see that the volume, pressure and temperature are changing, considering that the vapor pressure of water at 0 °C or also 273 K is 0.006 atm, the pressure of dry hydrogen would be 0.99 atm, thus, we can write:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

Now, as we need the final volume V2, by solving for it, we write:

$V_2=\frac{P_1V_1T_2}{T_1P_2}$

In such a way, we plug in the given data to obtain:

$V_2=\frac{0.97atm*2.0L*273K}{298K*0.99atm}\\\\V_2=1.80L$

Which means that the underwent a compression.

Best regards!

Answer 2

Taking into account the combined gas law, the volume of the dry hydrogen gas at 273 K and a pressure of 1 atm is 1.78 L.

• Gay Lussac's Law

Gay-Lussac's law states that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Mathematically, this law indicates that the quotient between pressure and temperature is constant:

$\frac{P}{T}=k$

• Boyle's Law

Boyle's law says that the volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure.

Boyle's law is expressed mathematically as:

P× V = k

• Charles's law

Charles's law states that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, temperature and volume are directly proportional.

In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio that exists between the volume and the temperature will always have the same value:

$\frac{V}{T}=k$

• Combined gas law

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{PxV}{T}=k$

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

$\frac{P1xV1}{T1}=\frac{P2xV2}{T2}$

• This case

In this case you know:

• P1= 0.97 atm
• V1= 2 L
• T1= 298 K
• P2= 1 atm
• V2= ?
• T2= 273 atm

Replacing in the combined gas law:

$\frac{0.97 atmx2 L}{298 K}=\frac{1 atmxV2}{273 K}$

Solving:

$\frac{0.97 atmx2 L}{298 K}\frac{273 K}{1 atm} =V2$

1.78 L= V2

In summary, the volume of the dry hydrogen gas at 273 K and a pressure of 1 atm is 1.78 L.

Learn more about the combined gas law:

• https://brainly.com/question/4147359?referrer=searchResults