Question

What happens if you try to compile and run this program?
#include <stdio.h>
int main (void) {
int i = 1, j = 0, k;
k = (i >> j) + G >> i) + (i >> i) + (j >>
k <<= i;
printf("%d", k):
return 0;
}​

Answer 1

Answer:

identifier "G" is undefined

Explanation:

The syntax of the code you provided is incorrect, so you cannot run this program.